Measuring - Router Forums
Old 05-19-2010, 01:36 PM Thread Starter
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Measuring

OK, I'm sure some of you are going to think this is a really stupid question or problem to have. I'm a smart guy. But you ever get one of those things where, for whatever reason, you can't get your head around the concept?

I'm trying to build a version of Norm's Chop Saw Station. I wanted to have it done this weekend, so the next could be for another project, so ordering the plans isn't going to work. I think I gleaned enough info off of the show to make my own. With all respect to Norm and the website, I won't be divulging any, but it wasn't hard to figure out. (any numbers you see here are mentioned by him)

What my brain is fried over is trying to measure (beveled/mitered/slant/whateverthecorrecttermis) cuts. The bottom of the table is supported by 5" rails, with spacers in between - so I assume these are the same dimension. The end spacers are splayed at a 10 degree angle to accept the legs. I know how to make all of this, but what I can't seem to understand is how to make sure everything is the same 5" width.

The only thing I can think of is to measure out what was cut off, and add to the original 5" to get the same distance, but even that doesn't sound right.

I tried Pythagorean Theorem, but the numbers don't make sense. Unless I reverse the known angle. Then I come up with a length of 5.0771, which sounds plausible.

Buying a miter saw, I think this kind of calculation is going to factor in much more with my work. Especially when you have two such angled cuts, and you have to make something to go in-between. Am I thinking about this too hard?
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Old 05-19-2010, 02:09 PM Thread Starter
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5.0771 is indeed the correct answer.

But how do y'all go about planning and measuring out things like this?
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Old 05-20-2010, 05:41 AM Thread Starter
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60+ views and nothing to share?
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Old 05-20-2010, 07:11 AM
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I'm having a hard time understanding about the bevels and angles.

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Old 05-20-2010, 07:34 AM
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Uhhhh..... Measure twice cut once...

I think everyone got scared off with the mention of "Pythagorean Theorem".
How the Heck do you rout (or is it route) one of those anyhow.
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Old 05-20-2010, 08:16 AM Thread Starter
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I'm not a wordsmith, so it may have been confusing.

Take a 6"x12"x3/4" piece of wood. This is oriented on a table standing on the grain edge, and all cuts are 90 degrees.

You need to end up with a second piece of wood with dimensions of N"x12"x3/4", and have it be exactly the same height, but at a 45 degree angle. To do that, the wood would have to be nearly 8.5". Easier to visualize? Like you're making legs for a table, and of course all the legs have to be the same height to make the table useful. But one or more of the legs have to sit at an angle. You're still trying to achieve the same overall height.

You can calculate the piece needed using a calculator, in hand or online. Like this one.

But I was wondering, how many of you have to do this, and are there any easy ways to think of it, or do it on a TS, MS, etc.
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Old 05-20-2010, 09:27 AM
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If you mean 45º from top to bottom, it would have to be a 12"x12" piece.

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Old 05-20-2010, 09:43 AM Thread Starter
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That's incorrect. It all goes back to Pythagorean Theorem.

a^2 + b^2 = c^2

In this case, since the angle is 45 degrees, both the a and b sides are equal. Since we know we want a side b that is 6" high, side a is the same.

6^2 + 6^2 = 72. sqrt 72 is 8.48xxx. 8.5"x12"x3/4" piece, set at a 45 degree angle would be the exact same height as a 6"x12"x3/4" piece, with the first number given as the height.

There's a way to express it inline, but sin and cos and tan have always given me problems.
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Old 05-21-2010, 08:25 PM
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What looks good by my eye has always worked well. No measuring, no fuss.

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Old 05-21-2010, 09:01 PM
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Math has never given me a problem until now. Now I,m really confused about wth it is your trying to cut and build. I know your just down the road in Kennesaw(Home of where everyone is required by law to own a gun). I,m just up from ya in Cartersville. Maybe I,ll drive down 1 day to see what the H**L you talkin about
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